# 418 Sentence Screen Fitting

### Problem:

Given a rows x cols screen and a sentence represented by a list of non-empty words, find how many times the given sentence can be fitted on the screen.

Note:

A word cannot be split into two lines. The order of words in the sentence must remain unchanged. Two consecutive words in a line must be separated by a single space. Total words in the sentence won't exceed 100. Length of each word is greater than 0 and won't exceed 10. 1 ≤ rows, cols ≤ 20,000. Example 1:

``````Input:
rows = 2, cols = 8, sentence = ["hello", "world"]

Output:
1

Explanation:
hello---
world---

The character '-' signifies an empty space on the screen.
``````

Example 2:

``````Input:
rows = 3, cols = 6, sentence = ["a", "bcd", "e"]

Output:
2

Explanation:
a-bcd-
e-a---
bcd-e-

The character '-' signifies an empty space on the screen.
``````

Example 3:

``````Input:
rows = 4, cols = 5, sentence = ["I", "had", "apple", "pie"]

Output:
1

Explanation:
apple
pie-I

The character '-' signifies an empty space on the screen.
``````

### Solutions:

``````public class Solution {
public int wordsTyping(String[] sentence, int rows, int cols) {
int count = 0;
int i = 0, j = 0;
int k = 0;
while (i < rows) {
if (count != 0 && j == 0 && k == 0) {
count = count * (rows / i);
i = (rows / i) * i;
}
if (k == sentence.length) {
count ++;
k = 0;
continue;
}
if (sentence[k].length() + j > cols) {
i ++;
j = 0;
continue;
}
else {
j = sentence[k].length() + j + 1;
k ++;
}
}
return count;
}
}
``````
``````public class Solution {
public int wordsTyping(String[] sentence, int rows, int cols) {
String s = "";
for (int i = 0; i < sentence.length; i ++) {
s += sentence[i] + " ";
}
int total = 0, len = s.length();
for (int i = 0; i < rows; i ++) {
total += cols;
if (s.charAt(total % len) == ' ') {
total ++;
}
else {
while ((total % len) > 0 && s.charAt((total % len) - 1) != ' ') {
total --;
}
}
}