485 Max Consecutive Ones

Problem:

Given a binary array, find the maximum number of consecutive 1s in this array.

Example 1:

Input: [1,1,0,1,1,1]
Output: 3
Explanation: The first two digits or the last three digits are consecutive 1s.
    The maximum number of consecutive 1s is 3.

Note:

1. The input array will only contain 0 and 1.
2. The length of input array is a positive integer and will not exceed 10,000

Solutions:

public class Solution {
    public int findMaxConsecutiveOnes(int[] nums) {
        int max = 0;
        int count = 0;
        for (int i = 0; i < nums.length; i ++) {
            if (nums[i] == 1) {
                count ++;
            }
            else {
                max = Math.max(max, count);
                count = 0;
            }
        }
        max = Math.max(max, count);
        return max;
    }
}